What if I need to differentiate 0 from NULL in C++? -


** please don't criticize purpose of code itself. it's pat morin's open data structures book. not first choice, assigned reading/practice. wanted know if there way differentiate, or better way go this. textbook--> http://opendatastructures.org/ods-cpp/**

** note: i'm coming java, allowed. code still compiles, "fixes" it**

i'm surprised nothing has come before because seems such simple question. perhaps it's buried or i'm not using correct terminology.

i have loop goes through data in vector. need return value being searched if it's found. if it's not found? here code.

int find(int x) {     for(int i=0;i<bag.size();i++){         // if x equal data, return data         if (bag[i]==x){             return bag[i]; // ends loop 1 instance found         }     }     // if made far, no match found.     return null;  } 

pretty simple. let's 0 1 of valid values might need record , search for. is, returns 0, not "null". research says 1 , same. how can specify or differentiate? other returning obsqure number won't come in program because may not have luxury (like -1 or -9999999). example, searching account balance. no number impossible.

why return value searching find function? know value, 1 passed function. return position of found element instead, information more useful. when value isn't found, can return special position, -1. or can follow model of standard library , return end iterator, signifies position 1 past end of range.


Comments

Popular posts from this blog

python - TypeError: start must be a integer -

c# - DevExpress RepositoryItemComboBox BackColor property ignored -

django - Creating multiple model instances in DRF3 -