sql - MySql: How to group by day and by hour each? SOLVED -

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there many questions here posted none one.

what trying query brings me count of records each hour day. see example in table below:

<table>   <tr>     <th>day/hour</th>     <th>0</th>     <th>1</th>     <th>2</th>     <th>4</th>     <th>5</th>     <th>6</th>     <th>7</th>     <th>8</th>     <th>9</th>     <th>10</th>     <th>11</th>     <th>12</th>     <th>13</th>     <th>14</th>     <th>15</th>     <th>16</th>     <th>17</th>     <th>18</th>     <th>19</th>     <th>20</th>     <th>21</th>     <th>22</th>     <th>23</th>   </tr>   <tr>     <td>2015-06-02</td>     <td>12</td>     <td>22</td>     <td>198</td>     <td>234</td>     <td>12</td>     <td>22</td>     <td>198</td>     <td>234</td>     <td>12</td>     <td>22</td>     <td>198</td>     <td>234</td>     <td>12</td>     <td>22</td>     <td>198</td>     <td>234</td>     <td>12</td>     <td>22</td>     <td>198</td>     <td>234</td>     <td>12</td>     <td>22</td>     <td>198</td>   </tr>   <tr>     <td>2015-06-01</td>     <td>3</td>     <td>342</td>     <td>1348</td>     <td>4</td>     <td>3</td>     <td>342</td>     <td>1348</td>     <td>4</td>     <td>3</td>     <td>342</td>     <td>1348</td>     <td>4</td>     <td>3</td>     <td>342</td>     <td>1348</td>     <td>4</td>     <td>3</td>     <td>342</td>     <td>1348</td>     <td>4</td>     <td>3</td>     <td>342</td>     <td>1348</td>   <tr> </table>

actually, how should displaying data (the table), how need resulset.

solution:

select date(created_at),          count(case hour(created_at) when 0 1 else null end) "0",          count(case hour(created_at) when 1 1 else null end) "1",          count(case hour(created_at) when 2 1 else null end) "2",          count(case hour(created_at) when 3 1 else null end) "3",          count(case hour(created_at) when 4 1 else null end) "4",          count(case hour(created_at) when 5 1 else null end) "5",          count(case hour(created_at) when 6 1 else null end) "6",          count(case hour(created_at) when 7 1 else null end) "7",          count(case hour(created_at) when 8 1 else null end) "8",          count(case hour(created_at) when 9 1 else null end) "9",          count(case hour(created_at) when 10 1 else null end) "10"          # , 13 more visitas group date(created_at);

since hours in day constant set not change time in foreseeable future, , since want display day-hour combinations no rows too, easiest thing may have 24 columns hardcoded in query:

select   date(date_col),          count (case hour(date_col) when 0 1 else null end) "0",          count (case hour(date_col) when 1 1 else null end) "1",          -- 22 more of these     my_table group date(date_col)

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