c# - RhinoMock - Use a real object, but stub a single method -

i'm writing unit test against mvc controller has dependency on ifoo. foo (the implementation) has 1 method i'd stub, want leave other intact. how can set using rhinomock?

foo has several dependencies i'd prefer not mock save writing additional lines of code , cluttering test.

foo :

public interface ifoo{     int method1();     int method2(); }  public class foo : ifoo{    //lot's of dependencies    public foo(ibar bar, ibaz baz, istackoverflow so){} } 

test:

[test] public void what_i_have_so_far(){     //arrange     //load real ifoo ninject (di)     var mockfoo = new ninject.kernel(new myexamplemodule())                     .get<ifoo>();      //i want test use real method1, not method2     //so stub method2     mockfoo        .stub(x => x.method2()) //<---- blows here        .returns(42);      //act     var controllerundertest = new controller(mockfoo); 

error:

using approach, rhinomock throws exception:

system.invalidoperationexception : object 'myapplication.myexamplemodule' not mocked object.

question:

how can stub method2?

i know create ifoo mock via mockrepository.generatemock, then'd i'd have copy real implementation of method1.

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update:

both brad , jimmy's solution seam work equally well, picked brad's because less code write.

however, after researching bit further, looks need automocker. there seams 1 structuremap , moq, not rhinomocks: https://github.com/rhinomocks/rhinomocks/issues/3

you have other way around. create mocked ifoo , redirect some calls real ifoo (this has done via whencalled extension):

var realfoo = new ninject.kernel(new myexamplemodule()).get<ifoo>(); var mockfoo = mockrepository.generatestub<ifoo>();  mockfoo.stub(f => f.method2()).return(42); mockfoo.stub(f => f.method1())    .whencalled(invocation =>    {        invocation.returnvalue = realfoo.method2();    })    .return(whatevervalue); 

the final return required though override few lines before. otherwise rhino throw exception.